Question

Vreau si explicație daca se poate.

Answer 1

45. a) x2 + xa+xm+am = x(x+a) + m(x+a) = (x+m)(x+a)

b) x2 - 4x-xm+4m = x(x-4)-m(x-4) = (x-4)(x-m)

c) x2 + 9*x + x*√5 + 9√5 = x(x+9)+√5(x+9) = (x+√5)(x+9)

d) x2 - x(b+√7) + b√7 = x2 - xb - x√7 + b√7 = x(x-b) - √7(x-b) = (x-√7)(x-b)

e)x2+ x(a-5) - 5a = x2 + ax - 5x - 5a = x(x+a) - 5(x+a) = (5-x)(x+a)

f) x2 + x(9+m) + 9m = x2+xm+9x+9m =  x(x+m)+9(x+m) = (x+9)(x+m)