Question

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Answer 1

a) m(AE)= 360-(70+80+50+40)= 360-240=120
b)m(BAC)=[m(AB)+m(BC)]/2=(70+80)/2=150/2=75
c)m(BAE)=[m(BC)+m(CD)+m(DE)]/2=(80+50+40)/2=170/2=85
d)m(BDC)=m(BC)/2=80/2=40
e)m(EDC)=[ m(AE)+m(AB)+m(BC)]/2=(120+70+80)/2=270/2=135
f)m(AEB)=m(AB)/2=70/2=35
g)m(EBD)=m(ED)/2=40/2=20
h)m(EDA)=m(AE)/2=120/2=60
i)m(ADC)=[m(AB)+m(BC)]/2=(70+80)/2=150/2=75
j)m(DCB)=[m(AB)+m(AE)+m(ED)]/2=(70+120+40)/2=230/2=115