Question

x+1/3 + x/2 = 1intreg si 1/6 - x

Answer 1

$\frac{x + 1}{3} + \frac{x}{2} = 1 \frac{1}{6} - x \\ \frac{2(x + 1)}{6} + \frac{3x}{6} = \frac{7}{6} - \frac{6x}{6} \\ 2x + 2 + 3x = 7 - 6x \\ 5x + 2 = 7 - 6x \\ 5x + 6x = 7 - 2 \\ 11x = 5 \\ = > x = \frac{5}{11}$
Din cerinta ta nu reiese daca x este in fractie sau nu. De aceea rezolv in ambele moduri si alegi tu varianta corecta.

$x + \frac{1}{3} + \frac{x}{2} = \frac{7}{6} - x \\ 6x + 2 + 3x = 7 - 6x \\ 9x +2 = 7 - 6x \\ 15x = 5 \\ x = \frac{1}{3}$

Answer 2

x + 1/3 + x/2 = 1 intreg 1/6 - x
x + 1/3 +x/2 =7/6 - x
6x+2+3x=7-6x
9x+2=7-6x
9x+6x=7-2
15x=5
x=5/15
x=1/3