Question

[x+1/3]=x-2
Va rog!!! [..]- parte intreaga !!!

Answer 1

Explicație pas cu pas:

Folosim [x]<=x<[x]+1

Avem [(x+1)/3]=x-2

=> [(x+1)/3]<=(x+1)/3<[(x+1)/3]+1 =>

x-2<=(x+1)/3<x-1 /*3 =>

3x-6<=x+1<3x-3

3x-6<=x+1 => 2x<=7 =>x<=7/2

x+1<3x-3 => 4<4x=> 1<x

=> 1<x<=7/2 => x€(1;7/2]