Question

( x+1+$\frac{2}{x-1}$ ) · $\frac{ x^{2-2x+1} }{ x^{3- x^{2} +x -1 } }$

Answer 1

[tex]E(x)=(x+1+ \frac{2}{x-1})* \frac{x^{2}-2x+1 }{x^{3}-x^{2}+x-1 } \\ E(x)= \frac{(x+1)(x-1)+2}{x-1}* \frac{ (x-1)^{2} }{ x^{2}(x-1)+(x-1) } \\ E(x)= \frac{ x^{2}-1+2 }{x-1}* \frac{ (x-1)^{2} }{(x-1)( x^{2}+1) } \\ E(x)= \frac{ x^{2} +1}{ x^{2}+1 } \\ E(x)=1 [/tex]