Question

x-1,x+1,4x+1 sa se determine x ,numerele date sunt in progresie geometrica

Answer 1

[tex](x+1)^2=(x-1)(4x+1)\\ x^2+2x+1=4x^2+x-4x-1\\ 3x^2-5x-2=0\\ \triangle=25+24=49\\ x_{1/2}= \frac{5\pm7}{6} \\ x_1=2\\ x_2=- \frac{1}{3} [/tex]