Question

√x+1=x-5 urgent va rog 

Answer 1

Punem initial C.E :x+1>0
                           x-5>0
  Ridicam la puterea a2-a si obtinem
$x+1= (x-5)^{2} => x+1= x^{2} -10x+25$
$x^{2} -11x+24=0$
obtii x1=3 si x2=8
acum verificam 3+1>0, dar 3-5<0, deci 3 nu convine
8+1>0, si 8-5>0, deci S={8}