Question

(X+10)+(x+24)+(x-2)=12

Answer 1

(x+10)+(x+24)+(x-2)=12
3x+32=12
3x+32-12=12-12
3x+20=0
3x=0-20
3x=-20
x=-20/3

Answer 2

$\displaystyle (x+10)+(x+24)+(x-2)=12 \\ x+10+x+24+x-2=12 \\ x+x+x=12-10-24+2 \\ 3x=-20 \\ x=- \frac{20}{3}$