Question

x:13=a,r7 y:13=b,r5 z:13=c,r5 aflati restul impartirii lui N=2x+3y+2z la 13
va rog mult !!!plssss

Answer 1

Răspuns:

rest 0

Explicație pas cu pas:

x:13=a,r7 => x=13a+7

y:13=b,r5 => y=13b+5

z:13=c,r5 =>z=13c+5

N=2x+3y+2z

N=2(13a+7)+3(13b+5)+2(13c+5)

N=2×13a+14+3×13b+15+2×13c+10

N=13(2a+3b+2c)+39

N=13(2a+3b+2c+3)

N:13=13(2a+3b+2c+3):13

N:13=2a+3b+2c+3, rest 0