Question

(x-19)x+(x+1)+(x+2)=128

Answer 1

sper ca te.am ajutatm succes :)

Answer 2

$x^{2} -19x+x+1+x+2=128$
[tex] x^{2} -17x+3=128 [/tex]
$x^{2} -17x=125$
x(x-17)=125
x(x-17)=5*25
x=5
x-17=25=>x=25+17=42