Question

x-1supra2      +2x+1 supra3=1-      2x+1supra 6,x apartine numerelor rationale

Answer 1

$\frac{x-1}{2} + \frac{2x+1}{3} = \frac{1-2x+1}{6}$
$\frac{3(x-1)+2(2x+1)}{6} = \frac{1-2x+1}{6}$
$\frac{3x-3+4x+2}{6} = \frac{1-2x+1}{6}$
3x-3+4x+2=1-2x+1
3x+4x+2x=1+1+3-2
9x=3
x=$\frac{3}{9}$
x=$\frac{1}{3}$    | => x ∈ Q