Question

x•√2+√2=0
-3√6+x√6=0
(2-√3)•x=√3-2
(1-√7)•x+√7-1=0
(2√10-1)•x-(1-2√10)la puterea a doua=0
(5-√5)x=√5(√5-1)
Va rog cat mai repede !!!!

Answer 1

x√2= -√2
x= -√2/√2
x= -1

x√6= 3√6
x=3√6/√6
x=3

(1-√7)x+√7=1
(1-√7)x= 1-√7
x=(1-√7)/(1-√7)
x=1

(2√10-1)x-1+4√10-40=0
(2√10-1)x-41+4√10=0
(2√10-1)x+4√10=41
(2√10-1)x=41-4√10
x=(41-4√10)/(2√10-1) rationalizam cu 2√10+1
x=(41-4√10)(2√10+1) supra 19= (82√10+41-80-4√10)/19=(78√10-39)/19

(5-√5)x=5-√5
x=(5-√5)/(5-√5)
x=1