Question

x^2+(2+2i)x +2i=0 Ajutor ! Sa se afle solutiile ecuatiei in C

Answer 1

delta = (2 + 2i)² - 4*2i= 4 + 8i - 4 - 8i = 0 => x1 = x2 = (-2-2i)/2 = -1-i

Answer 2

x²+(2+2i)x+2i=0
Δ=(2+2i)²-4*2i=4+4i²+8i-8i=4-4=0
x=-2(1+i)/2=-1-i