Question

(x-2)²-x²+8=0 Va rog aratatimi pasi pana la final

Answer 1

(a-b)² = a² - 2ab + b²

(x-2)² =  x² - 4x + 4    am desfacut dupa formula si rezolvam acum :

(x - 2)² - x² + 8 = 0

x² - 4x + 4  - x² + 8 = 0

- 4x =  -8 - 4

- 4x = - 12

4x = 12

x = 12 : 4

x = 3

Answer 2

Se poate face in doua moduri:
a)(x-2)²-x²+8=0
x²-4x+4-x²+8=0
-4x+12=0
-4x=-12
4x=12⇒x=3

b)(x-2)²-x²+8=0
(x-2-x)(x-2+x)+8=0
-2(2x-2)+8=0
-4x+4+8=0
-4x+12=0
-4x=-12
x=3