Question

(x^2-4)(9-x^2)=0
x apartine Z

Answer 1

$\rm (x^2-4)(9-x^2)=0 \\ (x+2)(x-2)(3+x)(3-x)=0 \\ x+2=0 \longrightarrow x=-2 \\ x-2=0 \longrightarrow x-2 \\ x+3=0 \longrightarrow x=-3 \\ 3-x=0 \longrightarrow x=3$