Question

(x-2)5+4≤(3x+2)3-4. :(

Answer 1

$\displaystyle (x-2) \cdot 5+4 \leq (3x+2) \cdot 3-4 \\ 5x-10+4 \leq 9x+6-4 \\ 5x-9x \leq 6-4+10-4 \\ -4x \leq 8 \\ 4x \geq -8 \\ x \geq - \frac{8}{4} \\ x \geq -2 \\ x \in [-2, \infty)$