Question

(x-2) la 2
(y+6) la 2
(√3+1) la 2
(3supra2 + 2b) la 2
Multumesc!

Answer 1

$1) {(x - 2)}^{2} = {x}^{2} - 2 \times x \times 2 + {2}^{2}$

$= {x}^{2} - 4x + 4$

$2) {(y + 6)}^{2} = {y}^{2} + 2 \times y \times 6 + {6}^{2}$

$= {y}^{2} + 12y + 36$

$3) {( \sqrt{3} + 1)}^{2} = {( \sqrt{3} )}^{2} + 2 \times \sqrt{3} \times 1 + {1}^{2}$

$= 3 + 2 \sqrt{3} + 1$

$= 4 + 2 \sqrt{3}$

$= 2(2 + \sqrt{3} )$

$4) {( \frac{3}{2} + 2b) }^{2} = {( \frac{3}{2}) }^{2} + 2 \times \frac{3}{2} \times 2b + {(2b)}^{2}$

$= \frac{ {3}^{2} }{ {2}^{2} } + \frac{2 \times 3 \times 2b}{2} + 4 {b}^{2}$

$= \frac{9}{4} + 6b + 4 {b}^{2}$

$= \frac{9}{4} + \frac{24b}{4} + \frac{16b^{2} }{4}$

$= \frac{9 + 24b + {16b}^{2} }{4}$

Answer 2

(x-2) ²= x²-2×2×x +2²= x²-4x +4
(y+6) ²= y²+2×6×y +6²=y²+12y+36
(√3+1)²=(√3)²+2×√3×1 +1²= 3+ 2√3+1= =4+2√3
(3/2 + 2b) ²= (3/2)²+2×3/2×2b +(2b) ²= 9/4+6b + 4b²