Question

(x+2)la putrea 2 + x la putrea 2 =(2x+1+(x+3)-3x+1

Answer 1

${(x + 2)}^{2} + {x}^{2} = (2x + 1) + (x + 3) - 3x + 1$

${x}^{2} + 4x + 4 + {x}^{2} = 2x + 1 + x + 3 - 3x + 1$

${x}^{2} + {x}^{2} + 4x - 2x - x + 3x = 1 + 3 + 1 - 4$

$2 {x}^{2} + 4x = 1$

$2 {x}^{2} + 4x - 1 = 0$

$a = 2$

$b = 4$

$c = - 1$

$\Delta = {b}^{2} - 4ac$

$\Delta = {4}^{2} - 4 \times 2 \times ( - 1)$

$\Delta = 16 + 8$

$\Delta = 24$

$x_{1,2}=\frac{-b\pm\sqrt{\Delta}}{2a}$

$x_{1,2}=\frac{-4\pm\sqrt{24}}{2 \times 2}$

$x_{1,2}=\frac{-4\pm2\sqrt{6}}{4}$

$x_{1}=\frac{-4 + 2\sqrt{6}}{4} = \frac{2( - 2 + \sqrt{6} )}{4} = \frac{ - 2 + \sqrt{6} }{2}$

$x_{2}=\frac{ - 4 - 2\sqrt{6}}{4} = \frac{2( - 2 - \sqrt{6} )}{4} = \frac{ - 2 - \sqrt{6} }{2}$