Question

x - 2 / pe x²-4x+4= ?

4x² -1 / pe 4x²-4x+1= ?

2y+ 1 / pe 4y²+2y= ?
Va rog dau coroana.

Answer 1

$\frac{x - 2}{ {x}^{2} - 4x + 4} = \frac{x - 2}{ {( x- 2)}^{2} } = \frac{1}{x - 2}$

$\frac{ 4{x}^{2} - 1 }{4 {x}^{2} - 4x + 1} = \frac{(2x - 1)(2x + 1)}{ {(2x - 1)}^{2} } = \frac{2x + 1}{2x - 1}$

$\frac{2y + 1}{4 {y}^{2} + 2y} = \frac{2y + 1}{2y(2y + 1)} = \frac{1}{2y}$