Question

(x^2+x+1)^2-(x^2-x+2)^2=0 repede varog...dau steluta

Answer 1

(x^2+x+1)^2-(x^2-x+2)^2=0
4x^3−2x^2+6x−3=0
(2x−1)(2x^2+3)=0
x= 1/2

sau

(x^2+x+1)^2-(x^2-x+2)^2=0
(x^2+x+1+x^2-x+2)(x^2+x+1-x^2+x-2)=0
(2x^2+3)(2x−1)=0
x= 1/2