Question

[(x-2)/(x+1)]-[(x-2)/(2x+2)]-[(x-2)/(6x+6)]=0,x nu este egal cu - 1​

Answer 1

Răspuns:

x = 2

Explicație pas cu pas:

$\frac{x-2}{x+1} - \frac{x-2}{2x+2} - \frac{x-2}{6x+6} = 0\\ \\ \frac{x-2}{x+1} - \frac{x-2}{2(x+1)} - \frac{x-2}{6(x+1)} = 0\Bigg | \cdot 6\\ \\ \frac{6(x-2) - 3(x-2) - (x-2)}{x+1} = 0\\ \\ \frac{2(x-2)}{x+1} = 0\\ \\ 2(x-2) = 0\\ \\ x-2 = 0\\ \\ x = 2$