Question

(x^2+x+2)^2-x^2+4x-4=

Answer 1

(x^2+x+2)^2-x^2+4x-4 =
= x^4 + x^2 + 4 + 2x^3 + 4x^2 + 4x - x^2 + 4x - 4 =
= x^4 + 2x^3 + 4x^2 + 8x

Folosesti formula de calcul prescurtat:

(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc 

Answer 2

=x^4 +x^2+4+2x^3+4x^2+4x-x^2+4x-4 = x^4+2x^3+4x^2+8x= x(x^3+2x^2+4x+8)
= x(x+2) (x^2+4)

     x^3+2x^2+4x+8 : x+2
   -x^3-2x^2               ------
-----------------            x^2+4
     =      =    4x+8
                   -4x-8
------------------------
                     =  =