Matematică, întrebare adresată de laurentiulau79, 9 ani în urmă

x/2-x/3=7/6. 2/3+x+1/2=5 intregi4-x/6

Răspunsuri la întrebare

Răspuns de Utilizator anonim
0
[tex] \frac{x}{2} - \frac{x}{3} = \frac{7}{6} \\\\ \frac{3*x}{3*2} - \frac{2*x}{2*3} = \frac{7}{6} \\\\ \frac{3x}{6} - \frac{2x}{6} = \frac{7}{6} \\\\ \frac{x}{6} = \frac{7}{6} \\\\ =\ \textgreater \ x= \frac{7*6}{6}\\\\ =\ \textgreater \ x= \frac{42}{6} \\\\ =\ \textgreater \ x=7[/tex][tex] \frac{2}{3} +x+ \frac{1}{2} =5 \frac{4-x}{6} \\\\ \frac{2}{3} + \frac{x}{1} + \frac{1}{2} = \frac{5}{1} * \frac{4-x}{6} \\\\ \frac{2}{3} + \frac{3*x}{3*1}+ \frac{1}{2} = \frac{5}{1}* \frac{4-x}{6} \\\\ \frac{2*2}{3*2} + \frac{2*3x}{3*1*2} + \frac{1*3*2}{2*3} = \frac{5}{1} * \frac{4-x}{6} \\\\ \frac{4}{6} + \frac{6x}{6} + \frac{6}{6} = \frac{5}{1} * \frac{4-x}{6} \\\\ \frac{10x}{6} + \frac{6}{6} = \frac{5}{1} * \frac{4-x}{6} \\\\ \frac{10x}{6} - \frac{4-x}{6} = \frac{5}{1} * \frac{6}{6} \\\\ [/tex][tex]=\ \textgreater \ \frac{10x}{6} - \frac{4-x}{6} = \frac{30}{6} \\\\ \frac{10x-4-x}{6} = \frac{30}{6}\\\\ 6x-x=5\\\\ 5x=5\\\\ x= \frac{5}{5} \\\\ =\ \textgreater \ x=1[/tex]

laurentiulau79: Diferite
laurentiulau79: Ca deaia e pus punctul
laurentiulau79: Multumesc
laurentiulau79: Ca mi le fici din nou
laurentiulau79: Incearca
Utilizator anonim: la primul x=7
Utilizator anonim: la al-2-lea x=1
Alte întrebări interesante