Question

X/2 =y/3=z/5 si 3x+2y-z=7 sa se determine nr. x,y,z dau 59 puncte

Answer 1

x/2=y/3⇒y=3x/2
x/2=z/5⇒z=5x/2
atunci
3x+2*3x/2-5x/2=7
3x+3x-5x/2=7
3x+x/2=7
7x/2=7
x/2=1
x=2

y=3x/2=3*2/2=3
z=5x/2=582/2=5
x=2
y=3
z=5
 verificare
 2/2=3/3=5/5
3*2+2*3-5=12-5=7
adevarate ambele , bine rezol;vat
as simple as that!!!