Question

X/2=y/3=z/7 x+y+z = 80
Ajutati-ma

Answer 1

 x      y      z
--- = --- = --- => din I + II => 3x=2y => x=(2/3)*y; din II si III => 7y=3z => 
 2     3      7

=> z=(7/3)*y

x+y+z=80 => (2/3)*y+y+(7/3)*y=80 => 12y/3=80 =>y=20
x=(2/3)*20=40/3
z=(7/3)*20=140/3