Question

x(2radical din2-radical din3)+2x(radical din 3-radical din2)=6+radical din3
2x(2+radical din3)-(radical din3-1)(x+2)=2x+6
2(x+radical din 2-radical din5)+3=x(radical din5-radical din2)
3(2radical din 2-5x)-2(x-3radical din2)=2(3xradical sin 2-4)-8x-10
(2x+1)radical din4-2radical din 3+(2x-1)radical din4+2radical din3=2 radical din 3(4-xradical din 3)+10
(x+1)(x-1)=x la 2+5x+4
x(1-x)+(2-x)la2+(3+x)la 2-1=(x-1)(4-x)+(2x+1)(2+x)
Plzzz coroana

Answer 1

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