Question

X+2y=17,y-3z=4 (2x+4y)×(X+4y-6z)
Tr

Answer 1

(2x+4y)x(X+4y-6z)=   {in prima si a doua paranteza il dam factor comun pe 2}

=[2(x+2y)]x[X+2(2y-3z)]=

=(2x17)x(X+2x2x4)=

=34x(X+16)= 

=34x+544=

X=544:34

X=16