Question

(x+3)²-2(x-1)=(x+4)(x-4)-5

Answer 1

(x+3)²-2(x-1)=(x+4)(x-4)-5=

x²+6x+9+(-2x+2)•(x²-16)-5=

x²+6x+9-2x³+32x+2x²-32-5=

3x²+6x+9-2x³+32x-32-5=

3x²+38x+9-2x³-32-5=

3x²+38x-28-2x³=

-2x³+3x²+38x-28

Answer 2

(x+3)²-2(x-1)=(x+4)(x-4)-5;
x²+6x+9-2x+2=x²-16-5;
x²+4x+11=x²-21 // se reduce x² cu x²;
x²+4x+11-x²+21=0;
4x=-32;
x=-32/4;
x=-8;