Question

(x-3)²-(x+1)²+3(x-2)(x+2)​

Answer 1

Răspuns:

$3x^2-8x-4$

Explicație pas cu pas:

$\left(x-3\right)^{2}-\left(x+1\right)^{2}+3\left(x-2\right)\left(x+2\right)\\=x^{2}-6x+9-\left(x^{2}-2x+1\right)+3\left(x^{2}-4\right)\\=x^{2}-6x+9-x^{2}-2x-1+3x^{2}-12\\=-8x-4+3x^{2}\\=3x^{2}-8x-4$

Answer 2

Răspuns:

(x-3+x+1)(x-3-x-1)+3(x²-4)=

(2x-2)(-4)+3x²-12=

-8x+8+3x²-12=

=3x²-8x-4