Question

(X-3)*-2(X-4)(X+4)+1-(X-5)(X+4)
*= la a 2-a
A.2 B.4 C.5 D.3

Answer 1

(x-3)²-2(x-4)(x+4)+1-(x-5)(x+4)=
=(x²-6x+9)-2(x²-16)+1-(x²+4x-5x-20)=
=x²-6x+9-2x²+32+1-x²-4x+5x+20=
=-2x²-5x+62

Answer 2

$(x-3)^2-2(x-4)(x+4)+1-(x-5)(x+4)= \\ =x^2-2*x*3+3^2-2(x^2-16)+1-(x^2+4x-5x-20)= \\ =x^2-6x+9-2x^2+32+1-x^2-4x+5x+20= \\ =-2x^2-5x+62$