Question

(x-3)^2-(x-8)^2=(radical 2x+1)^2-2x-10 in multimea numerelor reale :P

Answer 1

(x-3)^2 - (x-8)^2 = (radical 2x+1)^2 - 2x - 10
x^2 - 6x + 9 - (x^2 -16x + 64) = 2x + 1 - 2x - 10
x^2 - 6x + 9 - x^2 + 16x - 64 = -9
10 x - 55 = -9
10 x = 46
x = 46/10
x = 23/5
x = 4,6