Question

(x+3)[4(x + 4) – 3(x + 5)] <0
REPEDE ​

Answer 1

Răspuns:

sper ca te am ajutat! :*

Answer 2

Răspuns:

(x+3)(4x+16-3x-15)<0

4x²+16x-3x²-15x+12x+48-9x-45<0

x²+4x+3<0

∆=16-12=4; √∆=2

x¹= (-4-2)/2=(-3)

x²=(-4+2)/2=(-1)