Question

(x+3)la patrat +3(x-2) (x+2)=(2x-5) la patrat

Answer 1

Sunt fomulele speciale.
[tex](x+3)^{2} =x^{2} +2*x*3+ 3^{2} = x^{2} +6x+9 [/tex]
$(x-2)(x+2)= x^{2} -2^{2} = x^{2} -4$
$(2x-5)^{2} = (2x)^{2} -2*2x*5+5^{2} =4 x^{2} -20x+25$

Answer 2

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