Question

x +3 supra 2 plus 2x-1 supra 3 egal x supra 6

Answer 1

$\frac{x + 3}{2} + \frac{2x - 1}{3} = \frac{x}{6} \: | \times 6$

$\frac{6(x + 3)}{2} + \frac{6(2x - 1)}{3} = \frac{6x}{6}$

$3(x + 3) + 2(2x - 1) = x$

$3x + 9 + 4x - 2 = x$

$3x + 4x - x = - 9 + 2$

$6x = - 7$

$x = - \frac{7}{6}$