Question

(x+3) (x-2); va rog ajutatima

Answer 1

Salut,

(x+3)(x-2) = x(x-2)+3(x-2) = x²-2x+3x-6 = x²+x-6.

x²+x-6 = 0.

∆ = b²-4ac
∆ = 1+24
∆ = 25.

x1 = (-b-√∆)/2a
x1 = (-1-5)/2
x1 = -6/2
x1 = -3.

x2 = (-b+√∆)/2a
x2 = (-1+5)/2
x2 = 4/2
x2 = 2.


S = {-3;2}.



Succes! :3