Question

(x-3)(x-6)<(x-1)(x-2)

Answer 1

[tex] x^{2} -9x+18\ \textless \ x^{2} -3x+2 \\ -6x\ \textless \ -16 \\ 6x\ \textgreater \ 16 \\ x\ \textgreater \ \frac{16}{6} [/tex]
x∈($\frac{16}{6}$,∞)