Question

x\3 =y\5 =z\9 si A. x+y+z=34 B.x+z-y=21 gasiti x,y,z

Answer 1

x/3=y/5=z/9 = k
=> x=3k
=> y=5k
=> z=9k

A.
x+y+z=34
3k+5k+9k=34
17k=34
k=2
x=3•2=6
y=5•2=10
z=9•2=18

B.
x+z-y=21
3k+9k-5k=21
7k=21
k=3
x=3•3=9
y=5•3=15
z=9•3=27