Question

-x=4=2
x+3=1
3-6y=12
(x-2)*(4-y)=0

Answer 1

Răspuns:

-x=4=2

-x+4=2=>-x=2-4=>-x=-2=>x=2

-x-4=2=>=x=2+4=>x=-6

___________

x+3=1=>x=1-3=>x=-2

______________-

3-6y=12=>-6y=12-3=>y=y=-9/6=>y=-3/2=>y=-1,5

______________

(x-2)·(4-y)=0

x-2=0=>x=0+2=>x=2

4-y=0=>-y=0-4=>-y=-4=>y=4