Question

{[(x-49):4+2]•4+12}:4=125

Answer 1

{[(x-49):4+2]•4+12}:4=125

[(x/4-49/4+2(amplificam cu 4)•4+12]:4=125

[(x-49+8/4)•4+12]:4=125

[(x-49+8)+12]:4=125

(x-49+8+12):4=125

(x-49+20):4=125

(x-29) /4=125|•4

x-29=500

x=500+29

x=529