Question

x+4y pe 12  +2x+5y pe 12

Answer 1

$\frac{x+4y}{12}$ + $\frac{2x+5y}{12}$ = $\frac{x+4y+2x+5y}{12}$  = $\frac{3x+9y}{12}$ = $\frac{3(x+3y)}{12}$ = $\frac{x+3y}{4}$