Question

(x+7)pe3+(x+4)pe2 - (2x+5)pe3=?
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Answer 1

(x+7)/3 + (x+4)/2 - (2x+5)/3

Aducem fractiile la acelasi numitor adica 6

2(x+7)/2*3 + 3(x+4)/2*3 - 2(2x+5)/3*2=

= (2x + 14 + 3x+ 12 -4x -10)/6 =

= (5x - 4x + 14 + 12 -10)/6 =

= (x+16)/6