Question

x/7=y/6=z/5
z+y+z=32
Aflati x, y, z
(proportii derivate)

Answer 1

x+y+z=32
x/7=y/6= z/5 =k
x/7=k ⇒ x=7k
y/6=k ⇒ y=6k
z/5=k ⇒ z=5k
7k+6k+5k=32
18k=32
k=32/18 ⇒ k=16/9
x= 7 *16/9 ⇒ x= 112/9
y= 6*16/9 ⇒ y=96/9
z= 5* 16/9 ⇒ z=80/9