Question

x+7i=1-(4-y)i
(3x-2y)-(x-7y)i=-1-(y-4)i
ajutor,va rog

Answer 1

x+yi= a+bi  ⇔  x=a si y=b.  Partile reale, respectiv, coeficientii partilor imaginare trebuie sa fie egale
Dec: 1) x+7i=1-(4-y)i ⇔ x=1, 7=-4(4-y), adica y=23/4
2) (3x-2y)-(x-7y)i=-1-(y-4)i, ⇔ 3x-2y=-1 si (x-7y)=$(y-4)$,obtinem,sistemul$\left \{ {{3x-2y=-1} \atop {x-8y=-4}} \right.$,deci,x=8y-4,inlocuim,in,prima,24y-12-2y=-1,  obtinem y=1/2 si x=0