Question

x-8 radical din x plus 12 egal 0

Answer 1

x-8√x+12=0
(√x)²-8√x+12=0
Δ=64-4·12=16
x₁=(8+4)/2=6
x₂=(8-4)/2=2

Answer 2

[tex]x-8 \sqrt{x} +16-4=0 \\ ( \sqrt{x} -4)^{2} -4=0 \\ ( \sqrt{x} -4-2)( \sqrt{x} -4+2)=0 \\ ( \sqrt{x} -6)( \sqrt{x} -2)=0 \\ \sqrt{x} -6=0=> \sqrt{x} =6=>x=36 \\ \sqrt{x} -2=0=> \sqrt{x} =2=>x=4[/tex]
=>x aparține {4, 36}