Question

X kg aluminiu reactioneaza cu 16 kg oxid de fier si rezulta y kg fier. Sa se afle valorile lui x si y.
VA ROG AJUTATIMA RAPID
DAU COROANA!!!!!

Answer 1

MAl = 27kg/kmol , MFe2O3 = 160kg/kmol, MFe = 56kg/kmol

2Al + Fe2O3 => Al2O3 + 2Fe

2×27kg Al.........160kg Fe2O3..........2×56kg Fe
x kg Al..................16kg Fe2O3...........y kg Fe

x = 2×27×16/160 = 5,4kg Al
y = 2×56×16/160 = 11,2kg Fe

Answer 2

2Al+  Fe₂O₃ = 2Fe + Al₂O₃
subliniem formulele aluminiu,oxid de fier si fier,apoi se scriu masele moleculare ale substantelor 
MAl=27g           MFe₂O₃=( 56*2)+(16*3)=160g        MFe= 56 g
   
2* 27g Al..................160g Fe₂O₃.................2* 56g Fe
   x  Kg Al...................16Kg Fe........................y Kg  Fe

x= 2*27*16/ 160 = 5,4Kg  Al

y= 16*2*56/160 =11,2 Kg Fe