Question

x la a 2 +3x+2 ? Va rog

Answer 1

ax²+bx+c=a(x-x1)(x-x2)

x²+3x+2=0
a=1
b=3
c=2

∆=b²-4ac=3²-4*2*1=9-8=1

x1=(-b+√∆)/2a=(-3+√1)/2*1=(-3+1)/2=-2/2=-1

x2=(-b-√∆)/2a=(-3-√1)/2*1=(-3-1)/2=-4/2=-2

x1=-1 si x2=-2

→pentru ecuatie S={-2;-1)}

→pentru descompunerea in factori:
x²+3x+2=1*[x-(-1)][x-(-2)]=(x+1)(x+2)