Question

X la a 2 -6x+y la a 2-10y+34=0
Aflați x și y

Answer 1

[tex]x^2-6x+y^2-10y+34=0\\ (x^2-6x+9)+(y^2-10y+25)=0\\ (x-3)^2+(y-5)^2=0\\ \text{Dar cum:}(x-3)^2+(y-5)^2\geq 0,\text{ceea ce implica:}\\ \left \{ {{x-3=0} \atop {y-5=0}} \right.\Leftrightarrow \left \{ {{x=3} \atop {y=5}} \right. \\ S:(x,y)=(3,5)[/tex]