Question

x la a doua+(2m+1)ori x + m la a doua+ m =0

Answer 1

x²+(2m+1)x+(m²+m)=0
Δ=(2m+1)²-4(m²+m)=4m+4m+1-4m-4m=1

x(1)=(-(2m+1)-1)/2=-m
x(2)=(-(2m+1)+1)/2=-m+1

S={-m ; -m+1}