Question

X la a doua - 5x+6=0

Answer 1

Delta = b^2-4ac

delta=(-5)^2-4*1*6

delta=25-24

delta=1

x1=-b-radical delta/2a

x1=-(-5)-1/2

x1=5-1/2

x1=2

x2=-b+radical delta/2a

x2=-(-5)+1/2

x2=5+1/2

x2=3

Answer 2

x² - 5 x + 6 = 0

Δ = b² - 4 a c = 25 - 24

Δ = 1

x = ( -  b  ± √Δ ) / 2 a

x₁ = ( 5 + √1 ) / 2 ⇒  x₁ = 6 / 2 ⇒  x₁ = 3

x₂ = ( 5 - 1 ) / 2 ⇒  x₂ = 4 / 2  ⇒ x₂ = 2