Question

X la a doua -6X+5=0 varog frumos

Answer 1

x²-5x-x+5=0
x(x-5)-(x-5)=0
(x-5)(x-1)=0
 ca un produs sa fie 0 trebuie ca unul din factori sa fie 0
 x-5=0⇒ x=5

x-1=0⇒  x=1
Aceasta ecuatie de gradul 2v admite 2 solutii x=5 si x=1

verificare
 5²-6*5+5=25-30+5=0 adevarat
1²-6*1+5=1-6+5=0 adevarat

Answer 2

$x^{2}-6x+5=0$
$x=\dfrac{-(-6)\pm\sqrt{(-6)^{2}-4\cdot{1}\cdot{5}}}{2\cdot{1}}$
$x=\dfrac{6\pm\sqrt{36-20}}{2}$
$x=\dfrac{6\pm\sqrt{16}}{2}$
$x=\dfrac{6\pm4}{2}$

$x=\dfrac{6+4}{2}$
$x=\dfrac{6-4}{2}$

$x_{1}=\fbox{5}$
$x_{2}=\fbox{1}$

As simple as that ?